Mathématiques

Question

Aidez moi s'il vous plait. Niveau 3ème.

Calculer astucieusement:

a) 99 au carré
b)101x99
c)102 au carré
d)98 au carré
e)102x98
f)51x49
g)52x48
h)54x46

Merci d'avance de votre aide.

2 Réponse

  • bonjour

    99² = ( 100 - 1)² = 10 000 - 200 + 1 = 9 801
    101 x 99 = ( 100 + 1) ( 100 - 1) = 10 000 - 1 = 9 999
    102² = ( 100 + 2)² = 10 000 + 400 + 4 = 10 404
    98² = ( 100 - 2)² = 10 000 - 400 + 4 = 9 604
    102 x 98 = ( 100 + 2) ( 100 - 2) = 10 000 - 4 = 9 996
    51 x 49 = ( 50 + 1) ( 50 -1) = 2 500 - 1 = 2 499
    52 x 48 = ( 50 + 2) ( 50 -2) = 2 500 - 4 = 2 496
    54 x 46 = ( 50 + 4) ( 50 -4) = 2 500 - 16 = 2 484

  • 99² = (100-1)² = 10 000 -200 +1 = 9801

    101x99 =(100+1)(100-1) = 10 000 -100 +100 -1 = 9 999

    102² = (100+2)² = 10 000 +400 +4 = 10 404

    98² = (100-2)² = 10 000 -400 +4 = 9604

    102x98  = (100+2)(100-2) = 10 000 -200 +200 -4 = 9 996

    51x49 = (50+1)(50-1)  = 2500 -50+50-1 = 2449

    52x48 = (50+2)(50-2) = 2500-100+100-4 = 2496

    54 x46 = (50+4)(50-4) = 2500 -200+200-16 = 2484


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